Integrand size = 22, antiderivative size = 127 \[ \int \frac {(f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx=\frac {\left (d^2 g+e^2 f x\right ) (f+g x)}{4 d^2 e^2 \left (d^2-e^2 x^2\right )^2}+\frac {2 d^2 f g+\left (3 e^2 f^2-d^2 g^2\right ) x}{8 d^4 e^2 \left (d^2-e^2 x^2\right )}+\frac {\left (3 e^2 f^2-d^2 g^2\right ) \text {arctanh}\left (\frac {e x}{d}\right )}{8 d^5 e^3} \]
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Time = 0.04 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {753, 653, 214} \[ \int \frac {(f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx=\frac {\text {arctanh}\left (\frac {e x}{d}\right ) \left (3 e^2 f^2-d^2 g^2\right )}{8 d^5 e^3}+\frac {(f+g x) \left (d^2 g+e^2 f x\right )}{4 d^2 e^2 \left (d^2-e^2 x^2\right )^2}+\frac {x \left (3 e^2 f^2-d^2 g^2\right )+2 d^2 f g}{8 d^4 e^2 \left (d^2-e^2 x^2\right )} \]
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Rule 214
Rule 653
Rule 753
Rubi steps \begin{align*} \text {integral}& = \frac {\left (d^2 g+e^2 f x\right ) (f+g x)}{4 d^2 e^2 \left (d^2-e^2 x^2\right )^2}-\frac {\int \frac {-3 e^2 f^2+d^2 g^2-2 e^2 f g x}{\left (d^2-e^2 x^2\right )^2} \, dx}{4 d^2 e^2} \\ & = \frac {\left (d^2 g+e^2 f x\right ) (f+g x)}{4 d^2 e^2 \left (d^2-e^2 x^2\right )^2}+\frac {2 d^2 f g+\left (3 e^2 f^2-d^2 g^2\right ) x}{8 d^4 e^2 \left (d^2-e^2 x^2\right )}-\frac {\left (-\frac {3 e^2 f^2}{d^2}+g^2\right ) \int \frac {1}{d^2-e^2 x^2} \, dx}{8 d^2 e^2} \\ & = \frac {\left (d^2 g+e^2 f x\right ) (f+g x)}{4 d^2 e^2 \left (d^2-e^2 x^2\right )^2}+\frac {2 d^2 f g+\left (3 e^2 f^2-d^2 g^2\right ) x}{8 d^4 e^2 \left (d^2-e^2 x^2\right )}+\frac {\left (3 e^2 f^2-d^2 g^2\right ) \tanh ^{-1}\left (\frac {e x}{d}\right )}{8 d^5 e^3} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 110, normalized size of antiderivative = 0.87 \[ \int \frac {(f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx=\frac {-3 d e^5 f^2 x^3+d^5 e g (4 f+g x)+d^3 e^3 x \left (5 f^2+g^2 x^2\right )+\left (3 e^2 f^2-d^2 g^2\right ) \left (d^2-e^2 x^2\right )^2 \text {arctanh}\left (\frac {e x}{d}\right )}{8 d^5 e^3 \left (d^2-e^2 x^2\right )^2} \]
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Time = 0.43 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.06
method | result | size |
norman | \(\frac {\frac {f g}{2 e^{2}}+\frac {\left (d^{2} g^{2}-3 e^{2} f^{2}\right ) x^{3}}{8 d^{4}}+\frac {\left (d^{2} g^{2}+5 e^{2} f^{2}\right ) x}{8 d^{2} e^{2}}}{\left (-e^{2} x^{2}+d^{2}\right )^{2}}+\frac {\left (d^{2} g^{2}-3 e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{16 d^{5} e^{3}}-\frac {\left (d^{2} g^{2}-3 e^{2} f^{2}\right ) \ln \left (e x +d \right )}{16 d^{5} e^{3}}\) | \(135\) |
risch | \(\frac {\frac {f g}{2 e^{2}}+\frac {\left (d^{2} g^{2}-3 e^{2} f^{2}\right ) x^{3}}{8 d^{4}}+\frac {\left (d^{2} g^{2}+5 e^{2} f^{2}\right ) x}{8 d^{2} e^{2}}}{\left (-e^{2} x^{2}+d^{2}\right )^{2}}-\frac {\ln \left (-e x -d \right ) g^{2}}{16 d^{3} e^{3}}+\frac {3 \ln \left (-e x -d \right ) f^{2}}{16 d^{5} e}+\frac {\ln \left (e x -d \right ) g^{2}}{16 d^{3} e^{3}}-\frac {3 \ln \left (e x -d \right ) f^{2}}{16 d^{5} e}\) | \(152\) |
default | \(\frac {\left (d^{2} g^{2}-3 e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{16 d^{5} e^{3}}-\frac {-d^{2} g^{2}-2 d e f g -e^{2} f^{2}}{16 e^{3} d^{3} \left (-e x +d \right )^{2}}+\frac {-d^{2} g^{2}+2 d e f g +3 e^{2} f^{2}}{16 e^{3} d^{4} \left (-e x +d \right )}+\frac {\left (-d^{2} g^{2}+3 e^{2} f^{2}\right ) \ln \left (e x +d \right )}{16 e^{3} d^{5}}-\frac {-d^{2} g^{2}-2 d e f g +3 e^{2} f^{2}}{16 e^{3} d^{4} \left (e x +d \right )}-\frac {d^{2} g^{2}-2 d e f g +e^{2} f^{2}}{16 e^{3} d^{3} \left (e x +d \right )^{2}}\) | \(216\) |
parallelrisch | \(\frac {\ln \left (e x -d \right ) x^{4} d^{2} e^{5} g^{2}-3 \ln \left (e x -d \right ) x^{4} e^{7} f^{2}-\ln \left (e x +d \right ) x^{4} d^{2} e^{5} g^{2}+3 \ln \left (e x +d \right ) x^{4} e^{7} f^{2}-2 \ln \left (e x -d \right ) x^{2} d^{4} e^{3} g^{2}+6 \ln \left (e x -d \right ) x^{2} d^{2} e^{5} f^{2}+2 \ln \left (e x +d \right ) x^{2} d^{4} e^{3} g^{2}-6 \ln \left (e x +d \right ) x^{2} d^{2} e^{5} f^{2}+2 x^{3} d^{3} e^{4} g^{2}-6 x^{3} d \,e^{6} f^{2}+\ln \left (e x -d \right ) d^{6} e \,g^{2}-3 \ln \left (e x -d \right ) d^{4} e^{3} f^{2}-\ln \left (e x +d \right ) d^{6} e \,g^{2}+3 \ln \left (e x +d \right ) d^{4} e^{3} f^{2}+2 x \,d^{5} e^{2} g^{2}+10 x \,d^{3} e^{4} f^{2}+8 d^{5} e^{2} f g}{16 e^{4} d^{5} \left (e^{2} x^{2}-d^{2}\right )^{2}}\) | \(313\) |
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Leaf count of result is larger than twice the leaf count of optimal. 252 vs. \(2 (123) = 246\).
Time = 0.27 (sec) , antiderivative size = 252, normalized size of antiderivative = 1.98 \[ \int \frac {(f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx=\frac {8 \, d^{5} e f g - 2 \, {\left (3 \, d e^{5} f^{2} - d^{3} e^{3} g^{2}\right )} x^{3} + 2 \, {\left (5 \, d^{3} e^{3} f^{2} + d^{5} e g^{2}\right )} x + {\left (3 \, d^{4} e^{2} f^{2} - d^{6} g^{2} + {\left (3 \, e^{6} f^{2} - d^{2} e^{4} g^{2}\right )} x^{4} - 2 \, {\left (3 \, d^{2} e^{4} f^{2} - d^{4} e^{2} g^{2}\right )} x^{2}\right )} \log \left (e x + d\right ) - {\left (3 \, d^{4} e^{2} f^{2} - d^{6} g^{2} + {\left (3 \, e^{6} f^{2} - d^{2} e^{4} g^{2}\right )} x^{4} - 2 \, {\left (3 \, d^{2} e^{4} f^{2} - d^{4} e^{2} g^{2}\right )} x^{2}\right )} \log \left (e x - d\right )}{16 \, {\left (d^{5} e^{7} x^{4} - 2 \, d^{7} e^{5} x^{2} + d^{9} e^{3}\right )}} \]
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Time = 0.45 (sec) , antiderivative size = 144, normalized size of antiderivative = 1.13 \[ \int \frac {(f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx=- \frac {- 4 d^{4} f g + x^{3} \left (- d^{2} e^{2} g^{2} + 3 e^{4} f^{2}\right ) + x \left (- d^{4} g^{2} - 5 d^{2} e^{2} f^{2}\right )}{8 d^{8} e^{2} - 16 d^{6} e^{4} x^{2} + 8 d^{4} e^{6} x^{4}} + \frac {\left (d^{2} g^{2} - 3 e^{2} f^{2}\right ) \log {\left (- \frac {d}{e} + x \right )}}{16 d^{5} e^{3}} - \frac {\left (d^{2} g^{2} - 3 e^{2} f^{2}\right ) \log {\left (\frac {d}{e} + x \right )}}{16 d^{5} e^{3}} \]
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Time = 0.19 (sec) , antiderivative size = 152, normalized size of antiderivative = 1.20 \[ \int \frac {(f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx=\frac {4 \, d^{4} f g - {\left (3 \, e^{4} f^{2} - d^{2} e^{2} g^{2}\right )} x^{3} + {\left (5 \, d^{2} e^{2} f^{2} + d^{4} g^{2}\right )} x}{8 \, {\left (d^{4} e^{6} x^{4} - 2 \, d^{6} e^{4} x^{2} + d^{8} e^{2}\right )}} + \frac {{\left (3 \, e^{2} f^{2} - d^{2} g^{2}\right )} \log \left (e x + d\right )}{16 \, d^{5} e^{3}} - \frac {{\left (3 \, e^{2} f^{2} - d^{2} g^{2}\right )} \log \left (e x - d\right )}{16 \, d^{5} e^{3}} \]
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Time = 0.28 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.15 \[ \int \frac {(f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx=-\frac {3 \, e^{4} f^{2} x^{3} - d^{2} e^{2} g^{2} x^{3} - 5 \, d^{2} e^{2} f^{2} x - d^{4} g^{2} x - 4 \, d^{4} f g}{8 \, {\left (e^{2} x^{2} - d^{2}\right )}^{2} d^{4} e^{2}} + \frac {{\left (3 \, e^{3} f^{2} - d^{2} e g^{2}\right )} \log \left ({\left | e x + d \right |}\right )}{16 \, d^{5} e^{4}} - \frac {{\left (3 \, e^{3} f^{2} - d^{2} e g^{2}\right )} \log \left ({\left | e x - d \right |}\right )}{16 \, d^{5} e^{4}} \]
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Time = 0.11 (sec) , antiderivative size = 114, normalized size of antiderivative = 0.90 \[ \int \frac {(f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx=\frac {\frac {x^3\,\left (d^2\,g^2-3\,e^2\,f^2\right )}{8\,d^4}+\frac {f\,g}{2\,e^2}+\frac {x\,\left (d^2\,g^2+5\,e^2\,f^2\right )}{8\,d^2\,e^2}}{d^4-2\,d^2\,e^2\,x^2+e^4\,x^4}-\frac {\mathrm {atanh}\left (\frac {e\,x}{d}\right )\,\left (d^2\,g^2-3\,e^2\,f^2\right )}{8\,d^5\,e^3} \]
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